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| -rw-r--r-- | papers/2.tex | 7 | ||||
| -rw-r--r-- | papers/figures/2-2.pdf | bin | 0 -> 76634 bytes | |||
| -rw-r--r-- | papers/figures/gfx-strings.tex | 26 |
3 files changed, 27 insertions, 6 deletions
diff --git a/papers/2.tex b/papers/2.tex index 79915af..ddd3dc8 100644 --- a/papers/2.tex +++ b/papers/2.tex @@ -422,12 +422,7 @@ boundary, as pictured below.\footnote{Greenough, ``Higher-Order operators makes no difference, there will always be an insufficient number of objects in the series to fill all categories. -% \includegraphics[width=6.30006in,height=2.89763in]{media/image2.png} -\begin{center} - \begin{tikzpicture} - \node at (0, 0) {\texttt{[GRAPHICS FORTHCOMING]}}; - \end{tikzpicture} - \end{center} +\includegraphics[width=0.925\textwidth]{papers/figures/2-2.pdf} In conclusion, even though the rigid hierarchy in Keefe's structure might be defended to some extent, her appeal to an infinite hierarchy is fundamentally in conflict with the finite Sorites. There seems to be no diff --git a/papers/figures/2-2.pdf b/papers/figures/2-2.pdf Binary files differnew file mode 100644 index 0000000..f4e6eee --- /dev/null +++ b/papers/figures/2-2.pdf diff --git a/papers/figures/gfx-strings.tex b/papers/figures/gfx-strings.tex new file mode 100644 index 0000000..4021a61 --- /dev/null +++ b/papers/figures/gfx-strings.tex @@ -0,0 +1,26 @@ +\documentclass{article} +\usepackage{ebgaramond-maths} +\usepackage{amsmath} +\usepackage{amssymb} +\usepackage{mathastext} +\DeclareMathSymbol{0}{\mathalpha}{operators}{`0} +\DeclareMathSymbol{1}{\mathalpha}{operators}{`1} +\DeclareMathSymbol{2}{\mathalpha}{operators}{`2} +\DeclareMathSymbol{3}{\mathalpha}{operators}{`3} +\DeclareMathSymbol{4}{\mathalpha}{operators}{`4} +\DeclareMathSymbol{5}{\mathalpha}{operators}{`5} +\DeclareMathSymbol{6}{\mathalpha}{operators}{`6} +\DeclareMathSymbol{7}{\mathalpha}{operators}{`7} +\DeclareMathSymbol{8}{\mathalpha}{operators}{`8} +\DeclareMathSymbol{9}{\mathalpha}{operators}{`9} +\begin{document} + \noindent + $D_1F$ \bigskip \\ + $\neg D_1F \; \& \; \neg D_1 \neg F$ \bigskip \\ + $D_1\neg F$ \bigskip \\ + $D_2D_1F$ \bigskip \\ + $\neg D_2 D_1 F \; \& \; \neg D_2 \neg D_1 F$ \bigskip \\ + $D_2 \neg D_1 F \; \& \; D_2 \neg D_1 \neg F$ \bigskip \\ + $\neg D_2 D_1 \neg F \; \& \; \neg D_2 \neg D_1 \neg F$ \bigskip \\ + $\neg D_3 D_2 D_1 F \; \& \; \neg D_2 \neg D_2 \neg D_1 F$ \\ +\end{document}
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